Question

A certain mass of a gas occupies a volume of 2 dm³ at STP. At what temperature the volume of gas becomes double, keeping the pressure constant?

Options

• 540.15°C

• 400.15°C

• 546.15°C

• 273.15°C

Answer 1

273.15°C

Explanation:

V₁ = 2 dm³, T₁ = 273.15 K

V₂ = 4 dm³, T₂ = ?

According to Charle's law,

`"V"_1/"T"_1 = "V"_2/"T"_2`

`therefore "T"_2 = ("V"_2 xx "T"_1)/"V"_1`

`therefore "T"_2 = (4 xx 273.15)/2` = 546.3 K

Now, T k = t° C + 273.15

∴ t° C = T k - 273.15

∴ t° C = 546.3 - 273.15 = 273.15° C