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Karnataka Board PUCPUC Science Class 11

A Certain Salt X, Gives the Following Results.Its Aqueous Solution is Alkaline to Litmus. It Swells up to a Glassy Material Y On Strong Heating. - Chemistry

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Question

A certain salt X, gives the following results.

  1. Its aqueous solution is alkaline to litmus.
  2. It swells up to a glassy material Y on strong heating.
  3. When conc. H2SO4 is added to a hot solution of X, white crystal of an acid Z separates out.

Write equations for all the above reactions and identify X, Y and Z.

Answer in Brief

Solution

The given salt is alkaline to litmus. Therefore, X is a salt of a strong base and a weak acid. Also, when X is strongly heated, it swells to form substance Y. Therefore, X must be borax.

When borax is heated, it loses water and swells to form sodium metaborate. When heating is continued, it solidifies to form a glassy material Y. Hence, Y must be a mixture of sodium metaborate and boric anhydride.

NaA2BA4OA7Borax (X)+7HA2Owater2NaOHSodium hydroxide+4HA3BOA3Orthoboric acid

NaA2BA4OA710HA2OBorax (X)ΔNaA2BA4OA7Sodium metaborateΔBA2OA3Boric anhydric(Glassy material)+2NaBOA2

When concentrated acid is added to borax, white crystals of orthoboric acid (Z) are formed.

NaA2BA4OA710HA2OBorax (X)+HA2SOA4ΔNaA2SOA4+4HA3BOA3+5HA2OOrthoboric acid

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Some Important Compounds of Boron
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Chapter 11: The p-Block Elements - EXERCISES [Page 333]

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NCERT Chemistry - Part 1 and 2 [English] Class 11
Chapter 11 The p-Block Elements
EXERCISES | Q 11.30 | Page 333
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