Question

A change of 9.0 mA in the emitter current brings a change of 8.9 mA in the collector current. The value of current gain β will be ______.

Options

• 96

• 99

• 89

• 79

Answer 1

A change of 9.0 mA in the emitter current brings a change of 8.9 mA in the collector current. The value of current gain β will be 89.

Explanation:

ΔI_E = 9.0 mA

ΔI_C = 8.9 mA

`beta=(DeltaI_"C")/(DeltaI_"B")`

I_E = I_B + I_C

`therefore1/beta=(DeltaI_"B")/(DeltaI_"C")=(I_"E"-I_"C")/I_"C"=I_"E"/I_"C"-1`

`=9/8.9-1=90/89-1=1/89`

∴ β = 89