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A charge of 25 C is moved from infinity to points A and B in an electric field when the work done to do so is 10 J and 10.5 J respectively. - Physics

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Question

A charge of 25 C is moved from infinity to points A and B in an electric field when the work is done to do so is 10 J and 10.5 J respectively. Calculate the potential difference between points A and B.

Sum

Solution

WA = 10 J 

Charge Q = 25 C

Potential at point A = V1 = `"W"_"A"/"Q"`

V1 = `10/25 = 0.4` V

Also, WB = 10.5 J

Potential at point B = V2 = `"W"_"B"/"Q"`

V2 = `10.5/25 = 0.42` volt

A potential difference between A and B = V

V = V2 - V1 

V = 0.42 - 0.40

V = 0.02 volt

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Chapter 10: Electricity and Magnetism – 1 - Unit I Practice Problems 5

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Goyal Brothers Prakashan A New Approach to ICSE Physics Part 1 [English] Class 9
Chapter 10 Electricity and Magnetism – 1
Unit I Practice Problems 5 | Q 2
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