Question

A charge Q is applied to a conducting sphere of radius R. At the sphere's centre, the electric potential and electric field are respectively

Options

• `"Q"/(4πε_0"R")` and zero 

• `"Q"/(4πε_0"R") "and" "Q"/(4πε_0"R"^2)` 

• zero and `"Q"/(4πε_0"R"^2)` 

• Both are zero 

Answer 1

`"Q"/(4πε_0"R")` and zero 

Explanation:

At the centre of the conducting sphere of radius R, the

electric potential (JI) and electric field (E) are respectively.

V = `"Q"/(4πε_0"R")` and E = 0