Question

A charged particle is accelerated through a potential difference of 12 kV and acquires a speed of 10⁶ ms^-1. It is projected perpendicularly into the magnetic field of strength 0.2 T. The radius of the circle described is ______ cm.

Options

• 11.00

• 12.00

• 13.00

• 14.00

Answer 1

A charged particle is accelerated through a potential difference of 12 kV and acquires a speed of 10⁶ ms^-1. It is projected perpendicularly into the magnetic field of strength 0.2 T. The radius of the circle described is 12.00 cm.

Explanation:

`R = (mv)/(qB)`

`q xx 12 xx 10^3 = 1/2m xx (10^6)^2`

`(24 xx 10^3)/10^12 = m/q`

R = `(24 xx 10^3 xx 10^6)/(10^12 xx 0.2)`

R = `12 xx 10^-2` m

R = 12 cm