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Question
A child was born on 13th January 1976 which was a Tuesday. What day of the week will be the child‘s birthday in the year 1986?
Options
Sunday
Friday
Saturday
Monday
Solution
Monday
Explanation:
We know that,
Number of odd days in a non-leap year = 1
Number of odd days in a Leap year = 2
As year 1976 is a leap year.
So, Number of odd day in 1976 = 2
Similarly, 1980, 1984 are two leap year.
between 1976 to 1986
Also, Number of non-leap year between 1976 to 1986 = 7 year
Total number of odd days
= 3 × 2 + 7 × 1 = 13 days
13 days = 1 week + 6 days
Hence, 13th January 1986 will be Monday.
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