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Question
A circular disc 'X' of radius 'R' made from iron plate of thickness 't' has moment of inertia 'Ix' about an axis passing through the centre of disc and perpendicular to its plane. Another disc 'Y' of radius '3R' made from an iron plate of thickness `("t"/3)` has moment of inertia 'Iy' about the s same as that of disc X. The relation between Ix and ly is ______.
Options
Iy = 9 Ix
Iy = Ix
Iy = 3 Ix
Iy = 27 Ix
Solution
A circular disc 'X' of radius 'R' made from iron plate of thickness 't' has moment of inertia 'Ix' about an axis passing through the center of disc and perpendicular to its plane. Another disc 'Y' of radius '3R' made from an iron plate of thickness `("t"/3)` has moment of inertia 'Iy' about the s same as that of disc X. The relation between Ix and ly is Iy = 27 Ix.
Explanation:
`"I"_x = ("M"_x"R"^2)/2 ...."M"_x = (pi"R"^2"t")rho`
`= (pi"R"^4"t"rho)/2`
`"I"_"y" = (3pi"R"^2"t" rho "R"^2 xx 9)/2 ..."M"_"y" = (pi 9"R"^2 "t"/3)rho`
`= (27 pi "t" rho "R"^4)/2`
`therefore 27 "I"_x = "I"_"y"`