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Question
A coil of n turns and resistance R Ω is connected in series with a resistance `"R"/2`. The combination is moved for time t second through magnetic flux ϕ1 to ϕ2, The induced current in the circuit is ______.
Options
`("n"(phi_1-phi_2))/(3"Rt")`
`(2"n"(phi_1-phi_2))/(3"Rt")`
`(2"n"(phi_1-phi_2))/("Rt")`
`("n"(phi_1-phi_2))/("Rt")`
Solution
A coil of n turns and resistance R Ω is connected in series with a resistance `"R"/2`. The combination is moved for time t second through magnetic flux ϕ1 to ϕ2, The induced current in the circuit is `(2"n"(phi_1-phi_2))/(3"Rt")`.
Explanation:
When a coil of n turns moves through a magnetic flux from ϕ1 to ϕ2, the emf induced in the coil is
`epsilon = -("nd"phi)/"dt"=(-n(phi_2-phi_1))/1=(n(phi_1-phi_2))/"t"` ...(i)
As, resistance R of coil and `"R"/2` are in series, so equivalent resistance is
`"R"_"eq"="R"+"R"/2=(3"R")/2` ...(ii)
The induced current in the circuit is,
`"I"="e"/("R"_"eq")=(n(phi_2-phi_1))/("t"((3"R")/2))=(2"n"(phi_1-phi_2))/(3"Rt")`