Question

A coin is tossed 3 times. List the possible outcomes. Find the probability of getting at least 2 heads

Answer 1

The possible outcomes if a coin is tossed 3 times is

S = {(HHH), (TTT), (HTT), (THT), (TEH), (THH), (HTH), (HHT)}

Let E₂ = Event of getting atleast 2 heads = {(HHT), (HTH), (THH), (HHH)}

∴ n(E₂) = 4

∴ ${\displaystyle P\left(E_2\right)=\frac{n\left(E_2\right)}{n\left(S\right)}=\frac{4}{8}=\frac{1}{2}}$