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Question
A company selected 4000 households at random and surveyed them to find out a relationship between income level and the number of television sets in a home. The information so obtained is listed in the following table:
Monthly income (in Rs) |
Number of Television/household | |||
0 | 1 | 2 | Above 2 | |
< 10000 | 20 | 80 | 10 | 0 |
10000 – 14999 | 10 | 240 | 60 | 0 |
15000 – 19999 | 0 | 380 | 120 | 30 |
20000 – 24999 | 0 | 520 | 370 | 80 |
25000 and above | 0 | 1100 | 760 | 220 |
Find the probability of a household not having any television.
Sum
Solution
The total number of the households selected by the company, n(S) = 4000
Number of households not having any television, n(E3) = 30
∴ Required probability = `(n(E_3))/(n(S)) = 30/4000 = 3/400`
Hence, the probability of a household not having any television is `3/400`.
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