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A compound forms hexagonal close-packed structure. What is the total number of voids in 0.5 mol of it? How many of these are tetrahedral voids? -

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Question

A compound forms hexagonal close-packed structure. What is the total number of voids in 0.5 mol of it? How many of these are tetrahedral voids?

Options

  • 6.022 × 1023

  • 9.033 × 1023

  • 3.011 × 1023

  • 9.022 × 1023

MCQ

Solution

9.033 × 1023 

Explanation:

No. of atoms in 0.5 mole of the compound

0.5 × No = 0.5 × 6.022 × 1023 = 3.011 × 1023

No. of octahedral voids = no of atom = 3.011 × 1023

No. of tetrahedral voids = 2 × 3.011 × 1023 = 6.022 × 1023

Total no. of voids = (3.011 + 6.022) × 1023 = 9.033 × 1023

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Close Packed Structures of Solids
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