Question

A compound has a hep structure. Calculate the number of voids in 0.4 mol of it.

Answer 1

C = 0.4 mol.

Number of atoms

= 0.4 × N_A

= 0.4 × 6.023 × 10²⁴

= 2.4098 × 10²³

Number of tetrahedral voids

= 2 × Number of atoms

= 2 × 2.4098 × 10²³

= 4.818 x 10²³