Question

A compound microscope has a magnification of 30. The focal length of eye piece is 5 cm. Assuming the final image to be at least distance of distinct vision, find the magnification produced by the objective.

Answer 1

`"m"_"e" = "v"/"u" = "D"/"u"_"e" = 1 + "D"/"f"_"e"`

`= 1 + 25/5`

= 6 

for compound microscope,

m = m₀ × m_e

30 = m₀ × 6

m₀ = `30/6` = 5