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Question
A conducting loop of resistance R and radius r has its centre at the origin of the coordinate system in a magnetic field of induction B. When it is rotated about y-axis through 90°, the net charge flown in the loop is directly proportional to:
Options
R-1
R
r2
r
MCQ
Solution
r2
Explanation:
Apply 2nd law of electromagnetic induction
ε = `("d"phi)/"dt" ⇒ int_(phi_1)^(phi_2) d phi = Delta phi = int epsilon "dt"`
The total charge flown in the loop q = `int`Idt
or q = `int epsilon/"R""dt" = (Delta phi)/"R" = ("B"pi"r"^2)/"R" `
i.e. q ∝ B, q ∝ r2, and q ∝`1/"R"`
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