Question

A conductivity cell dipped in 0.01 M AgNO₃ solution gives a resistance of 3160 ohms. If cell constant is 0.47 cm⁻¹, what is the conductivity of AgNO₃ solution?

Options

• 6.723 × 10⁻² Ω⁻¹ cm⁻¹

• 1.487 × 10⁻² Ω⁻¹ cm⁻¹

• 1.487 × 10⁻⁴ Ω⁻¹ cm⁻¹

• 7.10 × 10⁻² Ω⁻¹ cm⁻¹

Answer 1

1.487 × 10⁻⁴ Ω⁻¹ cm⁻¹

Explanation:

Conductivity = Conductance × cell constant

= `1/"R" xx "cell constant"`

= `1/3160 xx 0.47`

= 0.0001487 Ω⁻¹ cm⁻¹

= 1.487 × 10⁻⁴ Ω⁻¹ cm⁻¹