Question

A conductivity cell dipped in 0.5 M KCl gives a resistance of 250 ohms. If the conductivity of KC I solution is 6.68 × 10^-3 S cm^-1, what is the cell constant?

Options

• 1.67 cm^-1

• 0.364 cm^-1

• 0.810 cm^-1

• 0.270 cm^-1

Answer 1

1.67 cm^-1 

Explanation:

Conductivity = Conductance × cell constant

K = C × cell constant

K = `1/"R"`× cell constant

6.68 × 10^-3 = `1/250`× cell constant

Cell constant = 6.68 × 10^-3 × 250

= 1670 × 10^-3 = 1.67 cm^-1