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Question
A conductor in the form of a circular arc of the radius of curvature R subtends an angle Ø at its centre of curvature. If the current in the conduct is I, the magnetic induction at the centre of curvature is ______.
Options
`B = (μ_0ØI)/(2R)`
`B = μ_0/(4π) (2ØI)/R`
`B = (μ_0I)/(2R)`
`B = μ_0/(4π) (ØI)/R`
MCQ
Fill in the Blanks
Solution
A conductor in the form of a circular arc of the radius of curvature R subtends an angle Ø at its centre of curvature. If the current in the conduct is I, the magnetic induction at the centre of curvature is `bbunderline(B = μ_0/(4π) (ØI)/R)`.
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Faraday's Laws of Electromagnetic Induction
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