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A conductor lies along the Z-axis at −1.5 ≤ Z ≤ 1.5 m and carries a fixed current of 10.0 A in −az​ direction as (see figure). For a field B = 3.0 × 10−4exe−0.2xay ​T, -

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Question

A conductor lies along the Z-axis at −1.5 ≤ Z ≤ 1.5 m and carries a fixed current of 10.0 A in −az​ direction as (see figure). For a field B = 3.0 × 10−4`"e"^(−0.2"x")`ay ​T, find the power required to move the conductor at constant speed to x = 2.0 m, y = 0 in 5 × 10−3 s. Assume parallel motion along the x-axis.

Options

  • 1.57 W

  • 2.97 W

  • 14.85 W

  • 29.7 W

MCQ

Solution

2.97 W

Explanation:

Force exerted on current carrying conductor (F) = BIl

Given, B = 3.0 × 10−4`"e"^(−0.2"x")`aI = 10.0 A​

Average power = `"Work done"/"Time taken"`

P = `1/"t"int_0^2"F"."d"x=1/"t"int_0^2"B"(x)"IL"."d"x`

P = `1/(5xx10^-3)int_0^2 3xx10^-4"e"^(-0.2x)xx10xx3"d"x` 

= 9`[1-"e"^-0.4]`

= 9 `[1-1/"e"^0.4]`

= 2.967 W = 2.97 W

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Power in AC Circuit
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