Question

A conductor of length 50 cm carrying a current of 5 A is placed perpendicular to a magnetic field of induction 2×10 ^-3T. Find the force on the conductor.

Answer 1

Given: conductor of length = 50 cm

Current I= 5 A
Magnetic induction B = 2×10 ^-3T
Solution:
Force on the conductor = ILB
= 5 × 50 × 10^-2 × 2 × 10^-3
= 5 × 10^-3