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Question
A cone of maximum volume is inscribed in a given sphere. Then the ratio of the height of the cone to the diameter of the sphere is ______.
Options
`3/4`
`1/3`
`1/4`
`2/3`
MCQ
Fill in the Blanks
Solution
A cone of maximum volume is inscribed in a given sphere. Then the ratio of the height of the cone to the diameter of the sphere is `underlinebb(2/3)`.
Explanation:
v = `1/3πR^2cos^2θ.R(1 + sinθ)`
`(dv)/(dθ) = R^3/3 (cos^3θ - 2cosθsinθ(1 + sinθ))` = 0
⇒ cos2θ = 2sinθ + 2sin2θ
(1 – sinθ)(1 + sinθ) = 2sinθ(1 + sinθ)
⇒ sinθ = `1/3`
h = `4/3`R
⇒ `h/(2R) = 2/3`
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