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Question
A cube of ice whose side is 4.0 cm is allowed to melt. The volume of water formed is found to be 58.24 cm3. Find the density of ice.
Solution
Side of ice cube = l = 4 cm
Volume of ice cube = V = β = (4)3 = 64 cm3
Volume of water = V = 5824 cm3
Density of ice cube = ρi= ?
Density of water = ρw = 1 gem-3
By law of floatation:
Volume of ice cube x Density of ice=Volume of water x Density of water
64 x ρi = 58.24 x 1
`rho_"i" = 58.24/64`
`rho_"i" = 0.91` g cm-3
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