Question

A current carrying closed loop in the form of a right angled isosceles ΔABC is placed in a uniform magnetic field acting along AB. If the magnetic force on the arm BC is F, then force on the arm AC is ______.

Options

• -F

• F

• `sqrt2"F"`

• `-sqrt2"F"`

Answer 1

A current carrying closed loop in the form of a right angled isosceles ΔABC is placed in a uniform magnetic field acting along AB. If the magnetic force on the arm BC is F, then force on the arm AC is -F.

Explanation:

Force along AB is zero as magnetic field is along AN.

The net force on a current carrying loop is always zero.

`vec"F"_"net"=vec"F"  "on"  "AB"+vec"F"  "on"  "BC"+vec"F"  "on"  "AC"`

`0=0+vec"F"+(vec"F"  "on"  "AB")`

we get, `vec"F"` on AC is `-vec"F"`