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A current I = 10 sin (50 π t) ampere is passed in the first coil which induces a maximum e.m.f. of 5 π volt in the second coil. The mutual inductance between the coils is ______. -

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Question

A current I = 10 sin (50 π t) ampere is passed in the first coil which induces a maximum e.m.f. of 5 π volt in the second coil. The mutual inductance between the coils is ______.

Options

  • 5 mH

  • 1 mH

  • 0.1 mH

  • 10 mH

MCQ
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Solution

A current I = 10 sin (50 π t) ampere is passed in the first coil which induces a maximum e.m.f. of 5 π volt in the second coil. The mutual inductance between the coils is 10 mH.

Explanation:

I = 10 sin (50 π t)

`"dI"/"dt" = 10 xx 50 cos 50 pi "t"`

e = `"M" xx "dI"/"dt"`

`therefore "M" = "e"/("dI"/"dt")`

`= (5pi)/(10 xx 50 pi) = 1/100` = 0.01 H = 10 mH

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