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Question
A cylindrical tub of radius 12 cm contains water to a depth of 20 cm. A spherical form ball is dropped into the tub and thus the level of water is raised by 6.75 cm. What is the radius of the ball?
Solution
A cylindrical tub of radius = 12cm
Depth = 20cm.
Let r cm be the radius of the ball
Then, volume of ball = volume of water raised
=`4/3πr^3 = π r^2h`
=`4/3πr^3 = π xx(12)^2 xx6.75`
⇒ `r^3=(144xx6.75xx3)/4`
⇒ `r^3=729`
⇒ r = 9cm
Thus, radius of the ball = 9cm.
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