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A Dealer Sells Two Refrigerators for Rs.37500 Each. on One He Makes a Profit of 25% While on the Other He Makes a Loss of 25%. Calculate His Overall Loss Or Profit Percentage in the Transaction. - Mathematics

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Question

A dealer sells two refrigerators for Rs.37500 each. On one he makes a profit of 25% while on the other he makes a loss of 25%. Calculate his overall loss or profit percentage in the transaction.

Sum

Solution

For the first refrigetator,
S.P. = Rs.37500
Profit = 25%
`"S.P."/"C.P." = 1 + ("Profit")/(100)`

⇒ `(37500)/"C.P." = 1 + (25)/(100)`

⇒ `(37500)/"C.P." = (100 + 25)/(100)`

⇒ C.P. = `(100)/(125) xx 37500`
= Rs.30000

For the second refrigerator,
S.P. = Rs.37500
Loss = 25%

`"S.P."/"C.P." = 1 - "Loss"/(100)`

⇒ `(37500)/"C.P." = 1 - (25)/(100)`

⇒ `(37500)/"C.P." = (100 -25)/(100)`

⇒ C.P. = `(100)/(75) xx 37500`
= Rs.50000
Total C.P.of both the refrigerator
= Rs.30000 + Rs.50000
= Rs.80000
Total S.P. of both the refrigerator
= Rs.37500 x 2
= Rs.75000
Since C.P. > S.P., so there is a loss
Loss
= C.P. - S.P.
= Rs.(80000 - 75000)
= Rs.5000
loss%
= `"Loss"/"C.P." xx 100`

= `(5000)/(80000) xx 100`
= 6.25%.

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Chapter 2: Profit , Loss and Discount - Exercise 2.2

APPEARS IN

Frank Mathematics [English] Class 9 ICSE
Chapter 2 Profit , Loss and Discount
Exercise 2.2 | Q 8

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