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Question
A dice is thrown 20 times and the outcomes are noted as shown below:
Outcomes | 1 | 2 | 3 | 4 | 5 | 6 |
No. of times | 2 | 3 | 4 | 4 | 3 | 4 |
Now a dice is thrown at random, find the probability of getting:
Solution
∵ Total number of outcomes = 20
(i) P (getting 3) = `4/20=1/5`
(ii) A number less than 3 (1, 2) will appear = 2 + 3 = 5 times
∴ Probability = `5/20=1/4`
(iii) A number greater than 3 (4, 5, 6) will appear = 4 + 3 + 4 = 11 times
∴ Probability = `11/20`
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