Question

A drop of water of radius 8 mm breaks into number of droplets each of radius 1 mm. How many droplets will be formed?

Answer 1

Radius of a big drop (R) = 8 mm,

Radius of a small drop (r) = 1 mm.

Number of droplets (n) = `"Volume of big drop"/"Volume of each droplet"`

`=(4/3piR^3)/(4/3pir^3)`

`n = (R/r)^3=(8/1)^3`

n = 512