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Question
A electric bulb is rate 220 V, 60 W. its electric cell resistance is nearly
Options
0.807 Ω
4 Ω
708 Ω
807 Ω
MCQ
Solution
807 Ω
Explanation:
R = `V^2/p`
`(220)^2/60 = (220 xx 220)/60` = 807 Ω
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