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Question
A first order reaction has a rate constant 0.00813 min-1. How long will it take for 60% completion?
Options
56.35 min
98.7 min
62.77 min
112.7 min
MCQ
Solution
112.7 min
Explanation:
Given,
Rate constant (k) = 0.00813 min-1
According to first order reaction, the relation is
t = `2.303/"k" log "a"/("a - x")`
As, a = 100, (a - x) = 100 - 60 = 40
∴ t = `2.303/0.00813 log 100/40`
`= 2.303/0.00813 xx log 2.5` ...[log 2.5 = 0.3979]
= 112.7 min
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