Question

A force of 50N is applied to the smaller piston of a hydraulic press. If the diameters of the piston are in the ratio 5 : 1, the force on the larger piston is ______.

Options

• 250 N

• 1000 N

• 1250 N

• 100 N

Answer 1

A force of 50N is applied to the smaller piston of a hydraulic press. If the diameters of the piston are in the ratio 5 : 1, the force on the larger piston is 1250 N.

Explanation:

F= 50 N

`"D"_"s"/"D"_l=1/5`

`therefore "area (small)"/"area (large)"=1/25`

∴ Pressure (small)= Pressure (large)

`50/1="force"/25`

∴ Force on large piston = 50 × 25 = 1250 N