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A four-digit number 4ab5 is divisible by 55. Then the value of b – a is ______. - Mathematics

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Question

A four-digit number 4ab5 is divisible by 55. Then the value of b – a is ______.

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Solution

A four-digit number 4ab5 is divisible by 55. Then the value of b – a is 1.

Explanation:

Given, a four-digit number 4ab5 is divisible by 55. Then, it is also divisible by 11.

The difference of sum of its digits in odd places and sum of its digits in even places is either 0 or multiple of 11.

i.e. (4 + b) – (a + 5) is 0 or a multiple of 11, if 4 + b – a – 5 = 0

⇒ b – a = 1

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Chapter 13: Playing With Numbers - Exercise [Page 409]

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NCERT Exemplar Mathematics [English] Class 8
Chapter 13 Playing With Numbers
Exercise | Q 8. | Page 409
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