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Question
A galvanometer has a resistance of 25 Ω and its full scale deflection current is 25 μA. What resistance should be added to it to have a range of 0-10 V?
Sum
Solution
Given G = 25 μA.
Maximum voltage to be measured is V = 10 V.
The galvanometer resistance G = 25 Ω.
The resistance to be added in series,
X = `"V"/"I"_"g" - "G"`
= `10/(25 xx 10^-6) - 25`
= 399.975 × 103 Ω
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