Question

A gaseous hypothetical chemical equation \[\ce{2A ⇌ 4B + C}\] is carried out in a closed vessel. The concentration of B is found to increase by 5 × 10⁻³ mol dm⁻³ in 10 second. The rate of ____________.

Options

• 5 × 10⁻⁴ mol dm⁻³ sec⁻¹

• 5 × 10⁻⁵ mol dm⁻³ sec⁻¹

• 6 × 10⁻⁵ mol dm⁻³ sec⁻¹

• 4 × 10⁻⁴ mol dm⁻³ sec⁻¹

Answer 1

A gaseous hypothetical chemical equation \[\ce{2A ⇌ 4B + C}\] is carried out in a closed vessel. The concentration of B is found to increase by 5 × 10⁻³ mol dm⁻³ in 10 second. The rate of 5 × 10⁻⁴ mol dm⁻³ sec⁻¹.

Explanation:

Increase in concentration of B = 5 × 10⁻³ mol dm⁻³; Time = 10 sec

Rate of appearance of B = `("Increase in the concentration of B")/("Time taken")`

= `(5 xx 10^-3  "mol dm"^-3)/(10  "sec")`

= 5 × 10⁻⁴ mol dm⁻³ sec⁻¹