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A Heavy Ring of Mass M is Clamped on the Periphery of Al Light Circular Disc. a Small Particle Having Equal Mass is Clamped at the Centre of the Disc - Physics

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Question

A heavy ring of mass m is clamped on the periphery of al light circular disc. A small particle having equal mass is clamped at the centre of the disc. The system is rotated in such a way that the centre moves in a circle of radius r with a uniform speed v. We conclude that an external force

Options

  • \[\frac{m v^2}{r}\] must be acting on the central particle

  • \[\frac{2m v^2}{r}\] must be acting on the central particle

  • \[\frac{2m v^2}{r}\] must be acting on the system

  • \[\frac{2m v^2}{r}\] must be acting on the ring. 

MCQ

Solution

\[\frac{2m v^2}{r}\] must be acting on the system 
Total mass of the system = 2m
To move the centre of the system in a circle of radius r with a uniform speed v, the external force required is
\[\frac{2m v^2}{R}\]

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Centre of Mass of a Uniform Rod
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Chapter 9: Centre of Mass, Linear Momentum, Collision - MCQ [Page 158]

APPEARS IN

HC Verma Concepts of Physics Vol. 1 [English] Class 11 and 12
Chapter 9 Centre of Mass, Linear Momentum, Collision
MCQ | Q 14 | Page 158

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