Question

(A) \[\ce{HOCl + H2O2 -> H3O^+ + Cl^- + O2}\]

(B) \[\ce{I2 + H2O2 + 2OH^- -> 2I^- + 2H2O + O2}\]

Choose the correct option.

Options

• H₂O₂ acts as oxidizing and reducing agent respectively in equations (A) and (B).

• H₂O₂ acts as oxidizing agent in equations (A) and (B).

• H₂O₂ acts as reducing agent in equations (A) and (B).

• H₂O₂ acts as reducing and oxidising agent respectively in equations (A) and (B).

Answer 1

H₂O₂ acts as reducing agent in equations (A) and (B).

Explanation:

When H₂O₂ reacts with HOCl, Cl⁻ (Chloride ion) is formed, implying that reduction occurs. Again, in the second equation, H₂O₂ reduces I₂ to the Iodide ion (I⁻), so H₂O₂ acts as a reducing agent in both equations (A) and (B).