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Tamil Nadu Board of Secondary EducationHSC Science Class 12

A lab assistant prepared a solution by adding a calculated quantity of HCl gas at 25°C to get a solution with [H3O+]= 4 × 10−5 M. Is the solution neutral (or) acidic (or) basic. - Chemistry

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Question

A lab assistant prepared a solution by adding a calculated quantity of HCl gas at 25°C to get a solution with [H3O+]= 4 × 10−5 M. Is the solution neutral (or) acidic (or) basic.

Numerical

Solution

[H3O+] = 4 × 10−5 M

pH = – log10 [H3O+]

pH = – log10 [4 × 10−5]

pH = – log10 [4] – log10 [10−5]

pH = – 0.6020 – (– 5)

= – 0.6020 + 5

pH = 4.398

Therefore, the solution is acidic.

Since pH is less than 7, the solution is acidic.

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Chapter 8: Ionic Equilibrium - Evaluation [Page 31]

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Samacheer Kalvi Chemistry - Volume 1 and 2 [English] Class 12 TN Board
Chapter 8 Ionic Equilibrium
Evaluation | Q 7. | Page 31
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