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Question
A light string passing over a smooth light pulley connects two block of masses m1 and m2 (vertically). If the acceleration of the system is (3g/7), then the ratio of masses is ____________.
Options
8 : 1
9 : 7
1.4 : 3
2.25 : 1
Solution
A light string passing over a smooth light pulley connects two block of masses m1 and m2 (vertically). If the acceleration of the system is (3g/7), then the ratio of masses is 2.25 : 1.
Explanation:
When two masses m1 and m2 are connected to the two ends of an inextensible string passing over a smooth frictionless pulley, then the acceleration of the masses is given by:
`"a"= (("m"_1 - "m"_2)/("m"_1 + "m"_2))"g"`
Here a= 3g/7
`therefore (3"g")/7 = (("m"_1 - "m"_2)/("m"_1 + "m"_2))"g"`
3m1 + 3m2 = 7m1 - 7m2
4m1 = 10 m2
`"m"_1/"m"_2 = 10/4`
`therefore "m"_1/"m"_2 = 2.25`