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A light string passing over a smooth light pulley connects two block of masses m1 and m2 (vertically). If the acceleration of the system is (3g/7), then the ratio of masses is ____________. -

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Question

A light string passing over a smooth light pulley connects two block of masses m1 and m2 (vertically). If the acceleration of the system is (3g/7), then the ratio of masses is ____________.

Options

  • 8 : 1

  • 9 : 7

  • 1.4 : 3

  • 2.25 : 1

MCQ
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Solution

A light string passing over a smooth light pulley connects two block of masses m1 and m2 (vertically). If the acceleration of the system is (3g/7), then the ratio of masses is 2.25 : 1.

Explanation:

When two masses m1 and m2 are connected to the two ends of an inextensible string passing over a smooth frictionless pulley, then the acceleration of the masses is given by:

`"a"= (("m"_1 - "m"_2)/("m"_1 + "m"_2))"g"`

Here a= 3g/7

`therefore (3"g")/7 = (("m"_1 - "m"_2)/("m"_1 + "m"_2))"g"`

3m1 + 3m2 = 7m1 - 7m2

4m1 = 10 m2

`"m"_1/"m"_2 = 10/4`

`therefore "m"_1/"m"_2 = 2.25`

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