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Question
A magnetised needle of magnetic moment 4.8 × 10-2 Am2 is placed at 30° with the direction of uniform magnetic field of magnitude 3 × 10-2 T. What is the torque acting on the needle?
Options
7.2 × 10-1 N-m
7.2 × 10-2 N-m
7.2 × 10-4 N-m
7.2 × 10-3 N-m
MCQ
Solution
7.2 × 10-4 N-m
Explanation:
Here, M = 44.8 × 10-2 Am2
θ = 30°, B = 3 × 10-2 T
As τ = MB sin θ
τ = 4.8 × 10-2 × 3 × 10-2 sin 30°
τ = 7.2 × 10-4 N-m
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