Question

A male rabbit of genotype 'AABBDDEE' is crossed with a female rabbit of genotype 'aabbddee' to produce F₁ hybrid offspring. How many genetically different gametes can be produced by this F₁ hybrid?

Options

• 4

• 8

• 16

• 32

Answer 1

16

Explanation:

The genotype of the F₁ hybrid would be AaBbDdEe.
The number of heterozygous alleles in an individual's gametes = 2ⁿ,
where n is the number of heterozygous alleles.

There are 4 heterozygous alleles in this situation.

As a result, n = 4 and
2ⁿ = 2⁴ = 16