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Question
A man bought two transistor radios which cost him Rs.7200. He sold one of them at a loss of 15% and the other at a gain of 19%. If the selling price of both the transactors is same, find the cost price of each.
Solution
C.P. of both the transistors = Rs.7200
Let C.P. of the 1st transistor be Rs. x
∴ C.P. of the 2nd transistor is Rs. (7200 - x)
For the 1st transistor,
Loss = 15%
∴ S.P.
= C.P. - Loss
= Rs. x - 15% of Rs. x
= Rs. 0.85x
For the 2nd transistor,
Profit = 19%
S.P.
= C.P. + profit
= Rs. (7200 - x) + 19% of Rs. (7200 - x)
= Rs. (8568 - 1.19x)
Given, both the S.P.'s are equal
∴ 0.85x = 8568 - 1.19x
⇒ 1.19x + 0.85x
= 8568
⇒ 2.04x = 8568
⇒ x = `(8568)/(2.04)`
= 4200
∴ C.P. of 1st transistor = Rs. 4200
C.P. of 2nd transistor
= Rs.7200 - Rs4200
= Rs.3000.
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