Question

A man buys an article and sells it at a loss of 10%. Had he bought it for 20% less and sold it for ₹55 more, he would have made a profit of 40%. The cost price of the article is

Options

• ₹200

• ₹225

• ₹250

• ₹300

Answer 1

₹250
Explanation : 
Let the cost price of article = x

Then selling price = `x-x xx10/100=(9x)/100`

If he had bought it for 20% less then

CP = `x-x xx20/100=(4x)/5`

and then SP = `(9x)/10+55`

Now, Profit% = `(((9x)/10+55)-(4x)/5)/((4x)/5)xx100`

⇒ `40xx(4x)/5xx1/100=x/10+55`

⇒ `16/50xx-x/10=55`

⇒ `(11x)/50=55`

⇒ `x=(55xx50)/11=250`