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Question
A man’s age is three times that of his son, and in twelve years he will be twice as old as his son would be. What are their present ages.
Solution
Let present age of the son = x years
present age of the man = 3x years
In 12 years :
Son’s age will be = (x + 12) years
The man’s age will be = (3x + 12) years
According to the statement :
3x + 12 = 2(x + 12)
⇒ 3x + 12 = 2x + 24
⇒ 3x – 2x = 24 – 12
⇒ x = 12
3x = 3 x 12 = 36
Hence, present age of the man = 36 years
Present age of the son = 12 years.
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