Advertisements
Advertisements
Question
A normal visioned woman whose father is colourblind married a normal visioned man. What are the probabilities of her sons or daughters to be colourblind? Explain with the help of Punnett square.
Solution
The genotype of woman - XCX (Carrier)
The genotype of man - XCY (Normal)
| Parents | Carrier woman | × | Normal man |
| Genotype | XCX | × | XCY |
| Gametes | XCX | XCY |
By Punnett's square :
 |
XC | Y |
 |
||
| XC | XCXC colourblind female |
XCY normal male |
| X | XCX carrier female |
XCY colourblind male |
APPEARS IN
RELATED QUESTIONS
The phenotypic ratio of incomplete dominance is ______.
Explain the Term Mutation.
Explain the term Alleles.
Give Technical Term:
A virus with DNA as heredity material.
Explain a dihybrid cross with suitable example and checker board method.
In a dihybrid cross with contrasting characters, the number of different genotypes obtained in F2 generation are ______.
The appearance of new combinations in the F2 generation of a dihybrid cross proves the law of ______.
Define Alleles.
Parents of blood group i and AB cannot have a child of blood group AB because ______.
Name any two genetic diseases in humans.
