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Question
A number consists of two digits and the digit in the ten's place exceeds that in the unit's place by 5. If 5 times the sum of the digits be subtracted from the number, the digits of the number are reversed. Then the sum of digits of the number is:
Options
11
7
9
13
MCQ
Solution
9
Explanation:
Let the unit's digits be x
Then tan's digit be x + 5
Number = 10(x + 5) + x = 10x + 50 + x = 11x + 50
Digits are reversed = 10x + x + 5
According to question
11x + 50 – 5(2x + 5) = 10x + x + 5
x + 25 = 11x + 5
10x = 20
x = 2
Sum of digits = 2x + 5 = 2 × 2 + 5 = 9
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