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Question
A particle executes S.H.M. of 2 cm. At the extreme position, the force is 4 N. What is the force at a point midway between mean and extreme positions?
Solution
Since F = kx …...(in magnitude)
∴ `"F"_2/"F"_1 = "x"_2/"x"_1`
∴ F2 = `1/2 xx 4` .....…(x1 = A = 2 cm, x2 = `"A"/2` = 1 cm, `"F"_1` = 4 N)
= 2 N
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