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Question
A particle executes S.H.M. of amplitude 3 cm. Its acceleration at extreme position is 27 cm/s2 Calculate its angular velocity.
Numerical
Solution
Given: a = 3 cm, amax = 27 cm/s2
amax = aω2
ω2 = `a_max/a=27/3 =9`
ω = 3 rad/sec
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Angular S.H.M. and It's Differential Equation
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