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Question
A particle having charge 100 times that of an electron is revolving in a circular path by radius 0.8 with one rotation per second. The magnetic field produced at the centre is
Options
`10^-17 muo`
`10^-17 /(muo)`
`10^-10 muo`
`10^-15 muo`
MCQ
Solution
`10^-17 /(muo)`
Explanation:
Equivalent current i = qv
= `100e xx 1 = 100 xx 1.6 xx 10^-19` A
Induction of a magnetic field in the centre.
B = `(mu_0)/(4pir) - (2pini)/r`
`(mu_0)/2 = (1 xx 100 xx 1.6 xx 10^-19)/.08 = 10^-17 muo`
Induction of a magnetic field at the centre.
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