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Question
A particle of mass m is rotating in a plane in a circular path of radius r. Its angular momentum is L. The centripetal force acting on the particle is ______.
Options
`"L"^2/"mr"`
`"mL"^2/"r"`
`"L"^2/"mr"^2`
`"L"^2/"mr"^3`
MCQ
Fill in the Blanks
Solution
A particle of mass m is rotating in a plane in a circular path of radius r. Its angular momentum is L. The centripetal force acting on the particle is `"L"^2/"mr"^3`.
Exlpanation:
Centripetal force = `"m"omega^2"r"`
∴ `omega = "L"/"I" = "L"/"mr"^2 ....[∵ "L"="I"omega]`
∴ `"F" ="m" ("L"/"mr"^2)^2 "r" = ("mL"^2 "r")/("m"^2"r"^4) = "L"^2/"mr"^3`
shaalaa.com
Angular Momentum or Moment of Linear Momentum
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