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A party has 20 participants. Find the number of distinct ways for the host to sit with them around a circular table. How many of these ways have two specified persons on either side of the host? - Mathematics and Statistics

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Question

A party has 20 participants. Find the number of distinct ways for the host to sit with them around a circular table. How many of these ways have two specified persons on either side of the host?

Sum

Solution

Here, n = Total number of participants = 20 + 1 host = 21

∴ the number of ways in which these 21 persons can be seated at a circular table = (n – 1)!

= (21 – 1)!

= 20!

Taking 2 specified persons and host as 1 unit, there are 18 + 1 = 19 persons.

Now 19 persons can be arranged in (19 – 1)! = 18! ways.

The host always occupies the centre position and two specified persons be seated on either side of the host in 2! ways.

Hence, the total number of circular arrangements in which two specified persons be seated on either side of the host = 18! × 2! = 2(18!).

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Permutations - Circular Permutations
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Chapter 3: Permutations and Combination - Exercise 3.5 [Page 61]

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